SOLUTION: there are two types of fish in the lake. fish type A has a current population of 5750 and is decreasing by 250 fish per year. fish type B has a current population of 3500 and is
Algebra ->
College
-> Linear Algebra
-> SOLUTION: there are two types of fish in the lake. fish type A has a current population of 5750 and is decreasing by 250 fish per year. fish type B has a current population of 3500 and is
Log On
Question 54917: there are two types of fish in the lake. fish type A has a current population of 5750 and is decreasing by 250 fish per year. fish type B has a current population of 3500 and is increasin by 500 per year. in how many years will the fish population in the lake be the same and what will the total fish population be? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! there are two types of fish in the lake. fish type A has a current population of 5750 and is decreasing by 250 fish per year. fish type B has a current population of 3500 and is increasin by 500 per year. in how many years will the fish population in the lake be the same and what will the total fish population be?
----------------
Let x be the number of years till the populations are equal.
EQUATION:
5750-250x = 3500+500x
2750=750x
x=3 2/3 yrs
Cheers,
Stan H.
(