SOLUTION: 4x+2y=8 y=2x+1 4x+2(2x+1)=8 y=2(8x-7)+1 4x+4x+1=8 y=16x-7+1 8x+1=8 y=16x-8 8x-7 Thats all i could figure out i do

Algebra ->  College  -> Linear Algebra -> SOLUTION: 4x+2y=8 y=2x+1 4x+2(2x+1)=8 y=2(8x-7)+1 4x+4x+1=8 y=16x-7+1 8x+1=8 y=16x-8 8x-7 Thats all i could figure out i do      Log On


   



Question 52495This question is from textbook
: 4x+2y=8 y=2x+1
4x+2(2x+1)=8 y=2(8x-7)+1
4x+4x+1=8 y=16x-7+1
8x+1=8 y=16x-8
8x-7
Thats all i could figure out i don't know how to simplfy it because we are doing substitution. any help would be greatly apperiated. thank you.
This question is from textbook

Answer by hayek(51) About Me  (Show Source):
You can put this solution on YOUR website!
Just work one equation at a time, and don't forget to distribute correctly.
4x%2B2y=8 and y=2x%2B1
4x%2B2%282x%2B1%29=8
4x%2B4x%2B2=8
8x%2B2=8
x=6%2F8 or x=3%2F4
Plug that into the other equation to get y:
y=2%283%2F4%29%2B1
y=10%2F4
y=2%261%2F2