SOLUTION: 1a.Stella is having a race with Tess. Stella gives Tess a 5o foot head start. Stella runs at 14.3 feet per second and Tess runs at 12.5 feet per second.
b.Write a system of e
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b.Write a system of e
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Question 512110: 1a.Stella is having a race with Tess. Stella gives Tess a 5o foot head start. Stella runs at 14.3 feet per second and Tess runs at 12.5 feet per second.
b.Write a system of equations for the two sisters distances.
c. How lon should the race be in order for it to be a close call.
I think b is
stella 14.3x - 50=y
and I am guessing
Tess is 12.5x=y
Please help!! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1a.Stella is having a race with Tess.
Stella gives Tess a 5o foot head start.
Stella runs at 14.3 feet per second and
Tess runs at 12.5 feet per second.
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Tess DATA:
rate = 12.5 ft/sec ; time = t sec ; distance = r*t = 12.5t ft.
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Stella DATA:
rate = 14.3 ft/sec ; time = t sec ; distance = r*t = 14.3t ft.
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b.Write a system of equations for the two sisters distances.
stella distance = tess distance + 50 ft.
14.3t = 12.5t + 50
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c. How long should the race be in order for it to be a close call.
Solve the equation for "r":
14.3t - 12.5t = 50
1.8t = 50
t = 27.78 sec
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Tina's distance 12.5*27.78 = 347.22 ft
Stella's distance 14.3*27.78 = 397.22 ft
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Cheers,
Stan H.
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