Question 48058: 1. -4(3-x)=2(x+6)
2. 5x+4y=6
-2x-3y=-1
Answer by sinadone(8)   (Show Source):
You can put this solution on YOUR website! Question #1. -4(3-x)=2(x+6)
Distribute the -4, meaning -4 multiplied by 3, and -4 multiplied by -x.
Also distribute the 2, meaning 2 multipplied by x and 2 multiplied by 6.
So far, it should look like this:
-12+4x=2x+12
The next step is moving the 2x to the left, making it a negative.
-12+4x=2x+12
-2x
The 2x cancels out on the right, and you add or subtract it to the 4x on the left. In this case, you'll be subtracting it because 4x is positive -2x is negative--remember, opposite signs, you subtract. So now your equation should look like this:
-12+2x=12
Now move the -12 to the right, because remember, you want to isolate 2x. It becomes a positive, so you add it to the right side. It should now look like this:
2x=24
Divide by 2 to isolate the x.
x=12
Question #2. 5x+4y=6
You want to isolate y, so you'll have an equation saying y = x+6 (just an example).
Move the 5x to the right side, becoming a negative. It should look like this:
4y=-5x+6
In order to get rid of the 4 on the left, divide by 4. Yes, you'll get a fraction. It looks like this:
y=-5/4x+3/2
Question #3. -2x-3y=-1
Isolate the y. Start by moving the -2x to the right.
-3y=2x-1
Then divide by -3:
y=-2/3x+1/3
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