SOLUTION: 11x-(6x-5)=40 could u xplain how 2 do it. im stuck.

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Question 4710: 11x-(6x-5)=40 could u xplain how 2 do it. im stuck.
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
First step is to remove the parentheses by the distributive property. Sometimes it helps to write your original problem with a 1 before the parentheses:
11x - 1(6x - 5) = 40
11x - 6x + 5 = 40

Combine like terms on the left side:
5x + 5 = 40

Subtract 5 from each side of the equation:
5x + 5 - 5 = 40 - 5
5x = 35

Divide each side of the equation by 5:
5x+%2F5+=+35%2F5
x+=+7

Check in the original equation:
11x - (6x-5) = 40
11%2A7+-+%286%2A7+-+5%29+=+40
77+-+%2842-5%29+=+40
77-+37+=+40
40+=+40 It checks!!

R^2 at SCC