Question 443014: solve substitution method 9x - 6y=-33 and 3x + 19=y
Answer by angelagallegos(8)   (Show Source):
You can put this solution on YOUR website! 1)First thing you want to do is look to see which equation will be easier to plug into the other first.
2)I see that the equation y= 3x+19 is already solved for y
3) take 9x-6y=-33 and plug in the first equation in for y.
9x-6(3x+19)=-33
4) distribute the -6 to the 3x and 19 9x-18x-114= -33
5) add the like terms (x's) together- -9x-114= -33
6) get -9x by itself on one side, add 114 to both sides
7) this will leave you with -9x=81.
8) again get x on one side, divide both sides by -9. x= -9
Now you know what the value of x is, you will take that value and plug it in to the second equation. y=3x+ 19 you do this by:
1) where you see the x you will plug in -9
y= 3(-9) +19
2) multiply and add y= -27 +19
3) y= -8
4) this will give you the ordered pair of ( -9, -8) you want to make sure this is correct.
To do this, you will check the answer by plugging the pair into each equation, it must work in both equations in order to be the correct pairs.
CHECK:
1) 9(-9)-6(-8)=-33
-81 +48 = -33
-33 = -33 True
2) 3(-9) + 19 = -8
-27 + 19 = -8
-8 = -8 true
Your answer is (-9, -8)
Hope this helps
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