SOLUTION: A guy has 30 coins consisting of nickels dimes and quarters. He has 3 more dimes than nickels. The total of the coins is $3.55. find the number of quarters. (I have done problem
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Question 3606: A guy has 30 coins consisting of nickels dimes and quarters. He has 3 more dimes than nickels. The total of the coins is $3.55. find the number of quarters. (I have done problems like this before without any problems but this one is giving me a really hard time. It seems simple but i cant get the correct solution..??? Answer by AnlytcPhil(1806) (Show Source):
You can put this solution on YOUR website! A guy has 30 coins consisting of nickels dimes and quarters. He has 3 more
dimes than nickels. The total of the coins is $3.55. Find the number of
quarters. (I have done problems like this before without any problems but this
one is giving me a really hard time. It seems simple but I can't get the
correct solution..???
`
>>...a guy has 30 coins consisting of nickels dimes and quarters...<<
`
` ` ` ` ` ` ` ` `N + D + Q = 30
`
>>...he has 3 more dimes than nickels...<<
`
` ` ` ` ` ` ` ` ` ` ` ` `D = N + 3
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>>...The total money value of the coins is $3.55...<<
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` `$0.05N + $0.10D + $.25Q = $3.55
`
Dropping the dollar marks and multiplying thru by 100:
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` ` ` ` ` ` 5N + 10D + 25Q = 355
`
Since all those terms can be easily divided by 5, we can
simplify it to
`
` ` ` ` ` ` ` `N + 2D + 5Q = 71
`
Now we have this system of equations:
`
` ` ` N + D + Q = 30
` ` ` ` ` ` ` D = N + 3
` ` N + 2D + 5Q = 71
Can you solve this system of equations? If not post again.
`
Answer:10 nickels, 13 dimes 7 quarters
`
Edwin
