SOLUTION: Solve the following system of nonlinear equations 2xy=3 4x^2-8y^2=1

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Question 328152: Solve the following system of nonlinear equations
2xy=3
4x^2-8y^2=1
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.2xy=3
2.4x%5E2-8y%5E2=1
From eq. 1,
y=3%2F%282x%29
y%5E2=9%2F%284x%5E2%29
Substitute into eq. 2,
4x%5E2-8%289%2F%284x%5E2%29%29=1%7C%7C%7C%0D%0A%7B%7B%7B4x%5E2-18%2Fx%5E2=1
4x%5E4-18=x%5E2
4x%5E4-x%5E2-18=0
%284x%5E2-9%29%28x%5E2%2B2%29=0
One solution:
4x%5E2-9=0
4x%5E2=9
x%5E2=9%2F4
x=0+%2B-+3%2F2
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Now find y.
y=3%2F%282x%29
y=3%2F%282%2A%283%2F2%29%29%0D%0A%7B%7B%7By=1
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(-3/2,-1)
(3/2,1)
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