SOLUTION: Solve the following system of nonlinear equations y=-x^2-2x+14 y=x^3-6x^2+12x-2

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Question 327877: Solve the following system of nonlinear equations
y=-x^2-2x+14
y=x^3-6x^2+12x-2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Since they both equal y, set them equal to each other.
-x%5E2-2x%2B14=x%5E3-6x%5E2%2B12x-2
x%5E3-5x%5E2%2B14x-16=0
%28x-2%29%28x%5E2-3x%2B8%29=0
The real solution is x-2=0 or x=2.
Use either equation to solve for y.
y=-%282%29%5E2-2%282%29%2B14
y=-4-4%2B14
y=6
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