SOLUTION: Solve the following system of nonlinear equations y=x^4-x^2+2x-1 y=x^4+3x^2+2x-2

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Question 327876: Solve the following system of nonlinear equations
y=x^4-x^2+2x-1
y=x^4+3x^2+2x-2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E4-x%5E2%2B2x-1=x%5E4%2B3x%5E2%2B2x-2
4x%5E2=1
x%5E2=1%2F4
x=+0+%2B-+1%2F2
Now use either equation to solve for y.
x=1%2F2,y=%281%2F2%29%5E4-%281%2F2%29%5E2%2B2%281%2F2%29-1=1%2F16-1%2F4%2B1-1=-3%2F16
x=-1%2F2,y=%28-1%2F2%29%5E4-%28-1%2F2%29%5E2%2B2%28-1%2F2%29-1=1%2F16-1%2F4-1-1=-35%2F16
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