SOLUTION: I do not understand how to find the zeros of a function. The following is the problem that is giving me problems.If you could help I would be much appreciative.
f(x)=x^2+3x-10
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f(x)=x^2+3x-10
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Question 325374: I do not understand how to find the zeros of a function. The following is the problem that is giving me problems.If you could help I would be much appreciative.
f(x)=x^2+3x-10
thanks
becca Found 2 solutions by stanbon, Alan3354:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! f(x)=x^2+3x-10
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Ways to find zeroes:
1. graphing
2. factoring
3. Quadratic equation
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Your Problem factors nicely:
Think of 2 numbers whose product is -10
and whose sum is 3.
The numbers are +5 and -2
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Replace the 3x term by -5x+2x to get:
x^2 +5x-2x - 10 = 0
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Factor the 1st two and the last two terms separately:
x(x+5) -2(x+5) = 0
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Factor again:
(x+5)(x-2) = 0
Solve:
x+5 = 0 or x-2 = 0
x = -5 or x = +2
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Those are the zeroes.
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Cheers,
Stan H.
You can put this solution on YOUR website! I do not understand how to find the zeros of a function. The following is the problem that is giving me problems.If you could help I would be much appreciative.
f(x)=x^2+3x-10
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f(x)=x^2+3x-10
Find the values of x that make f(x) = 0
f(x)=x^2+3x-10 = 0
x^2+3x-10 = 0
This example can be factored.
(x + 5)*(x - 2) = 0
If the product is zero, one of the factors must be zero.
x + 5 = 0
x = -5
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x - 2 = 0
x = 2
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