SOLUTION: solve 10x^3+20x^2= -6x^3+6x

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Question 317960: solve 10x^3+20x^2= -6x^3+6x
Answer by Jk22(389) About Me  (Show Source):
You can put this solution on YOUR website!
10x^3+20x^2= -6x^3+6x
16x^3+20x^2-6x=0=2x(8x^2+10x-3), Delta=Sqrt(100+12*8)=Sqrt(196)=14
x=0 or x=(-10+14)/16=1/4 or x=-24/16=-3/2