Question 31750: Question:
Solve the system:
x^2+y^2=64
x+y=8
(A) {[0,0), (8,-8)}
(B) {(0,8), (8,0)}
(C) {(8,-8), (-8,-8)}
(D) {(0,-8), (-8,0)}
Thank you very much! Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! x^2+y^2=64..................I
x+y=8 ....Y=8-X
SUBSTITUTING IN EQN.I
X^2+(8-X)^2=64
X^2+64+X^2-16X=64
2X^2-16X=0
2X(X-8)=0
X=0 OR 8
SO Y=8 OR 0
B IS THE ANSWER