SOLUTION: y<x^2-12x+36

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Question 311991: y
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First plot, y=x%5E2-12x%2B36
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-12x%2B36%29+
Now choose a point not on the parabola.
(0,0) is an available point.
Test the inequality.
If the point satisfies the inequality, it's in the solution region.
If it doesn't, it's not in the solution region".
(0,0)
0%3C0-12%280%29%2B36
36%3E0
True, so (0,0) is in the solution region.
Shade the region containing (0,0).
.
.
.
Solved by pluggable solver: Plot Any Inequality
Graphing function y%3Cx%5E2-12x%2B36:

graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y%3Cx%5E2-12x%2B36+%29