SOLUTION: How many real solutions does the nonlinear system have?
x^2+y^2=13
-x^2+2y^2=14
(a) 0
(b) 1
(c) 2
(d) 3
(e) 4
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-> SOLUTION: How many real solutions does the nonlinear system have?
x^2+y^2=13
-x^2+2y^2=14
(a) 0
(b) 1
(c) 2
(d) 3
(e) 4
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Question 30250: How many real solutions does the nonlinear system have?
x^2+y^2=13
-x^2+2y^2=14
(a) 0
(b) 1
(c) 2
(d) 3
(e) 4 Answer by Fermat(136) (Show Source):
You can put this solution on YOUR website! x^2+y^2=13 is circle, centre the origin
-x^2+2y^2=14 is a hyperbola, centre the origin
As you can see there are 4 solutions
Ans:e
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