Question 30249: Solve:
x^2+y^2=16
x^2/25 +y^2/16 =1
Solutions:
a. no solution
b. [(0,-4), (0,4)]
c. [(0,-5), (0,5)]
d. [(-5,0), (5,0)]
Answer by Fermat(136)   (Show Source):
You can put this solution on YOUR website! This one is solved by simple observation.
x²+y²=16 is the eqn of a circle, centre the origin, with a radius of r = 4.
x²/5² + y²/4² = 1 is the eqn of an ellipse, centre the origin, with semi-major axis,a = 5 and semi-minor axis, b = 4.
As you can see there are only two points of intersection (when both functions have a common point with the same x- and y-coordinates)
The points of intersection are:
(0,4) and (0,-4)
================
|
|
|
