SOLUTION: can you please add this (3b^2 + 4x -10)+(-b^2 +5x + 6)...oh and this is 12th grade algebra

Algebra ->  College  -> Linear Algebra -> SOLUTION: can you please add this (3b^2 + 4x -10)+(-b^2 +5x + 6)...oh and this is 12th grade algebra      Log On


   

Question 260825: can you please add this (3b^2 + 4x -10)+(-b^2 +5x + 6)...oh and this is 12th grade algebra
Found 2 solutions by Theo, richwmiller:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
12th grade is last year in high school if I remember correctly.

would that be right?

equation is: 

           3b^2 + 4x - 10
plus:      -b^2 + 5x + 6


equals:    2b^2 + 9x - 4

you add all the like terms together.

3b^2 + (-b^2) = 3b^2 - b^2 = 2b^2

4x + 5x = 9x

-10 + 6 = -4

put them all together and you get:

2b^2 + 9x - 4

when you add numbers together with different signs, you simply subtract the smaller number from the larger number and give the sign of the larger number to the result.

that's why -10 + 6 = -4.

I subtracted 6 from 10 and got 4. since the larger number of 10 was negative, I made the sign of the result negative.

3b^2 - b^2 = 2b^2 as follows:

3b^2 is the same as b^2 + b^2 + b^2

b^2 + b^2 + b^2 - b^2 = b^2 + b^2 = 2 * b^2

same with 5x + 4x

5*x = x + x + x + x + x

4*x = x + x + x + x

add them together and you get:

x + x + x + x + x + x + x + x + x = 9 * x.














Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Stan just did this for you a few minutes ago!