SOLUTION: Can someone please point me in the right direction with this experiment. Probabilities and Binomial Experiments.
U.S. Population by Region. The U.S. population by region (in m
Algebra ->
College
-> Linear Algebra
-> SOLUTION: Can someone please point me in the right direction with this experiment. Probabilities and Binomial Experiments.
U.S. Population by Region. The U.S. population by region (in m
Log On
Question 252519: Can someone please point me in the right direction with this experiment. Probabilities and Binomial Experiments.
U.S. Population by Region. The U.S. population by region (in millions) for selected years is given in the table. Find the probability that a U.S. resident selected at random satisfies the following:
a.) lived in the West in 1997.
b.) lived in the Midwest in 1995.
c.) lived in the Northwest or Midwest in 1997.
d.) lived in the South or West in 1997.
e.) What are the odds that a randomly selected U.S. resident in 2000 was not from the South?
REGION 1995 1997 2000
Northwest 51.4 51.6 53.6
Midwest 61.8 62.5 64.4
South 91.8 94.2 100.2
West 57.7 59.4 63.2
(Answers) a. .222 b. .235 c. .426 d. .574 e. 302 to 167
You can put this solution on YOUR website! the first thing to do is finish the table with totals for us population for each year in question
REGION 1995 1997 2000
Northwest 51.4 51.6 53.6
Midwest 61.8 62.5 64.4
South 91.8 94.2 100.2
West 57.7 59.4 63.2
sum(1995)=51.4+61.8+91.8+57.7
sum(1997)=51.6+62.5+94.2+59.4=267.7
sum(2000)=53.6+64.4+100.2+63.2
a) lived in west in 1997
59.4/267.7=.2219=.222
so the part over the whole= probability