SOLUTION: Can someone please help. I cannot figure out the correct formula.
Using a Nonlinear System.
Modeling Circuit Gain. In electronics, cicuit gain is modeled by G = Bt/R + rt
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Using a Nonlinear System.
Modeling Circuit Gain. In electronics, cicuit gain is modeled by G = Bt/R + rt
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Question 252428: Can someone please help. I cannot figure out the correct formula.
Using a Nonlinear System.
Modeling Circuit Gain. In electronics, cicuit gain is modeled by G = Bt/R + rt, where “R” is the value of a resister, “t” is temperature, Rt is the value of R at temperature “t”, and B is a constant. The sensitivity of the circuit to temperature is modeled by S = BR/(R + Rt)^2. If B = 3.7 and "t" is 90K (Kelvin), find the values of R and Rt that will make G = .4 and S = .001.
Answer: R= 187 , Rt = 645 Answer by Theo(13342) (Show Source):
R is the nominal value of a resistor.
R[t] is the value of the resistor at a certain temperature.
B is a constant.
t is the temperature using the Kelvin Scale.
S is the sensitivity of the circuit to temperature.
Your problem is:
"If B = 3.7 and "t" is 90K (Kelvin), find the values of R and Rt that will make G = .4 and S = .001. (Answer: R= 187 , Rt = 645)"
We have:
B = 3.7
t = 90
G = .4
S = .001
We want to find R and R[t].
The first formula is:
Substituting in this formula gets:
We divide both sides of this equation by .4 and we multiply both sides of this equation by (R + R[t]) to get:
We solve for (R + R[t] to get:
The second formula is:
We substitute in this formula to get:
S and B were given.
R + R[t] was calculated from the first equation.
We multiply both sides of this equation by (832.5)^2 and we divide both sides of this equation by 3.7 to get:
We solve for R to get R = 187.325
Since R + R[t] = 832.5, this means that R[t] = 832.5 - 187.325 = 645.1875
we round these out to get:
R = 187
R[t] = 645
This agrees with the answers you provided.
The key was solving for R + R[t] together in the first equation and then using that value to solve for R in the second equation.
Once we knew R, getting R[t] was a simple matter of subtraction.