SOLUTION: The sum of twice a first number and five times a secod number is 92. If the second number is subtracted from five times the first number the result is 14. find the numbers.
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Question 224017: The sum of twice a first number and five times a secod number is 92. If the second number is subtracted from five times the first number the result is 14. find the numbers. Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! The sum of twice a first number and five times a second number is 92. If the second number is subtracted from five times the first number the result is 14. Find the numbers.
Step 1. Let x be first number.
Step 2. Let y be the second number.
Step 3. Let 2x+5y=92 since the sum of twice a first number and five times a second number is 92.
Step 4. Also, 5x-y=14 since the second number is subtracted from five times the first number the result is 14.
Step 5. We have a system of equations given by Steps 3 and 4.
Solve: We'll use substitution. After moving 5*y to the right, we get: , or . Substitute that
into another equation: and simplify: So, we know that y=16. Since , x=6.
Answer: .
Step 6. ANSWER: The numbers are 6 and 16.
I hope the above steps and explanation were helpful.
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