SOLUTION: log (x2y4/z3) log8 (x3y4/z5) log2 (x/y2z3) logx243=5

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Question 223239: log (x2y4/z3)
log8 (x3y4/z5)
log2 (x/y2z3)
logx243=5
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log (x2y4/z3)
= 2log(x) + 4log(y) - 3log(z)
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log8 (x3y4/z5)
= 3log8(x) + 4log8(y) - 3log(z)
---------------------------------------
log2 (x/y2z3)
= log2(x) - 2log2(y) - 3log2(z)
---------------------------------------
logx243=5
logx(243) = 5
x^5 = 243
x = 3
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Cheers,
Stan H.