SOLUTION: Find the equation of the line that passes through the point (2;1) and is parallel to the line y = 3/4 x + 7.

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Question 20890: Find the equation of the line that passes through the point (2;1) and is parallel to the line y = 3/4 x + 7.
Answer by algebrapro18(249) (Show Source):
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well since parallel lines have the same slope we know that the new line has a slope of 3/4 so now we can either solve the equation y=mx+b for b and then plug in or use the point slope formula.
solving for b we get
y=mx+b where m=3/4 x=2 and y=1
1=3/4(2)+b
1 = 3/2+b
-1/2 = b
y=3/4x-1/2
using point-slope form you get
y-y1=m(x-x1) where m=3/4 y1=1 and x1=2
y-1=3/4(x-2)
y=3/4x-3/2+1
y=3/4x-1/2
*Note point slope form becomes very important in later math courses and is very helpeful for calculus so keep that in mind.