SOLUTION: I have tried to get some of these but I have a problem of being just a little off and then blowing the whole deal. Please help. Write standard form and identify a, b, and c. 4x

Algebra ->  College  -> Linear Algebra -> SOLUTION: I have tried to get some of these but I have a problem of being just a little off and then blowing the whole deal. Please help. Write standard form and identify a, b, and c. 4x      Log On


   



Question 187019: I have tried to get some of these but I have a problem of being just a little off and then blowing the whole deal. Please help.
Write standard form and identify a, b, and c.
4x² + 4 = 2x + 3
I need to solve this equation.
x(x-3) = 40 Would it be -5,-8?

Find the x-intercepts
Y = x² +4
And yet another one.
Y = x² -4x -32
Find the ordered pair for the vortex.
Y = 2x² -4x +6 Could it be (4,1)?
Solve the specified variable.
a/(l-r) for r Could it be r = a/s ?

Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
"Write standard form and identify a, b, and c.
4x² + 4 = 2x + 3 "

4x² + 4 = 2x + 3

4x² + 4 - 3 = 2x

4x² + 4 - 3 - 2x = 0

4x² - 2x + 1 = 0

Now in standard form: ax^2+bx+c = 0 ---> a = 4, b = -2x, and c = 1

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x(x-3) = 40

x^2-3x=40

x^2-3x-40=0

(x-8)(x+5)=0

x = 8 or x = -5

close...off by a sign

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x-intercepts:

Y = x² +4

0 = x² +4

x^2 = -4

x = sqrt(-4)

x = 2i or x = -2i

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x-intercepts:
Y = x² -4x -32


0= x² -4x -32


(x-8)(x+4)=0

x=8 or x=-4

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2x² -4x +6 ---> a=2, b=-4, c=6


x = -b/2a

x=-(-4)/(2(2))

x=4/4

x=1

y=2(1)^2-4(1)+6

y=2(1)-4(1)+6

y=2-4+6

y=4

Vertex: (1,4) ... mixed up coordinates

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can't solve a/(l-r) since it is not equation