SOLUTION: Let u = (1,-1,3,5) and v = (2,1,0,-3). Find scalars a and b so that au + bv = (1,-4,9,18). I would like to know the steps on how to solve for scalars a and b.

Algebra ->  College  -> Linear Algebra -> SOLUTION: Let u = (1,-1,3,5) and v = (2,1,0,-3). Find scalars a and b so that au + bv = (1,-4,9,18). I would like to know the steps on how to solve for scalars a and b.      Log On


   



Question 183071This question is from textbook Contemporary Linear Algebra
: Let u = (1,-1,3,5) and v = (2,1,0,-3). Find scalars a and b so that
au + bv = (1,-4,9,18).
I would like to know the steps on how to solve for scalars a and b.
This question is from textbook Contemporary Linear Algebra

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
au+bv = (1,-4,9,18) ... Start with the given equation

a(1,-1,3,5)+b(2,1,0,-3) = (1,-4,9,18) ... Plug in the given vectors


(a,-a,3a,5a)+(2b,b,0,-3b) = (1,-4,9,18) ... Multiply the scalars by EVERY element in the vectors


(a+2b,-a+b,3a,5a-3b) = (1,-4,9,18) ... Add the vectors by adding the corresponding components.


Now because both vectors on both sides are equal in dimension, this tells us that the left components correspond to the right components. This means that a%2B2b=1, -a%2Bb=-4, 3a=9, and 5a-3b=18



Which gives us the system of equations:

system%28a%2B2b=1%2C-a%2Bb=-4%2C3a=9%2C5a-3b=18%29


We can use any method to solve this system (substitution, elimination, matrix, etc), but notice how the third equation is composed of only one variable in which we can easily solve for.


Let's now solve the third equation 3a=9


3a=9 Start with the third equation.


a=9%2F3 Divide both sides by 3 to isolate "a".


a=3 Reduce.


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a%2B2b=1 Go back to the first equation.


3%2B2b=1 Plug in a=3


2b=1-3 Subtract 3 from both sides.


2b=-2 Combine like terms on the right side.


b=%28-2%29%2F%282%29 Divide both sides by 2 to isolate b.


b=-1 Reduce.


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Answer:


So the scalars are a=3 and b=-1


In other words,

3(1,-1,3,5)-1*(2,1,0,-3) = (1,-4,9,18)