SOLUTION: Write each function in vertex form. Sketch the graph of the function and label its vertex. 33. y = x2 + 4x - 7 34. y = -x2 + 4x - 1 35. y = 3x2 + 18x 36.y = 1/2x2 - 5x +

Algebra ->  College  -> Linear Algebra -> SOLUTION: Write each function in vertex form. Sketch the graph of the function and label its vertex. 33. y = x2 + 4x - 7 34. y = -x2 + 4x - 1 35. y = 3x2 + 18x 36.y = 1/2x2 - 5x +       Log On


   



Question 177856: Write each function in vertex form. Sketch the graph of the function and
label its vertex.

33. y = x2 + 4x - 7
34. y = -x2 + 4x - 1
35. y = 3x2 + 18x
36.y = 1/2x2 - 5x + 12

Found 2 solutions by stanbon, jojo14344:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write each function in vertex form. Sketch the graph of the function and
label its vertex.
33. y = x^2 + 4x - 7
x^2 + 4x + ? = y+7+?
x^2 + 4x + 4 = y+7+4
(x+2)^2 = y + 11
-----------------
Vertex: (-2,-11)
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2%2B4x-7%29
==================================================

34. y = -x^2 + 4x - 1
35. y = 3x^2 + 18x
-------------------------
36.y = 1/2x^2 - 5x + 12
(1/2)x^2 - 5x + ? = y-12 + ?
(1/2)[x^2 - 10x + ? = y-12 + ?
(1/2)[x^2 - 10x + 25] = y - 12 + (1/2)*25
(1/2)[x-5]^2 = y + (1/2)
----
Vertex: (5,-1/2))
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%281%2F2%29x%5E2-5x%2B12%29
============================
Cheers,
Stan H.

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

We know the standard eqn of a parabola: y=ax%5E2%2Bbx%2Bc
Being the vertex form---->y=a%28x-h%29%5E2%2Bk, where (h,k) is the vertex:
I'll do the first one, and you can continue the rest;
33. y+=+x2+%2B+4x+-+7--->follows std eqn, wheresystem%28a=1%2Cb=4%2Cc=-7%29
Complete the square, adding a constant by taking half of the "b" constant then squared. In this case the "b" constant is 4, half of it 4%2F2=2 then squared, 2%5E2=highlight%284%29:
y=%28x%5E2%2B4x%2Bhighlight%284%29%29-7-highlight%284%29, Also subtract what you added so the process won't change.
highlight%28y=%28x%2B2%29%5E2-11%29---->it follows the vertex form, being system%28h=x=-2%2Ck=y=-11%29
To get the x-intercept, we solve the eqn by Quadratic:
where---->system%28a=1%2Cb=4%2Cc-7%29

x=%28-4%2B-sqrt%2816%2B28%29%29%2F2=%28-4%2B-sqrt%2844%29%29%2F2=%28-4%2B-6.63%29%2F2
x=%28-4%2B6.63%29%2F2=2.63%2F2=highlight%281.32=x%29
x=%28-4-6.63%29%2F2=-10.63%2F2=highlight%28-5.32=x%29
For the Y-Intercept, let f%28x%29=0
y=0%5E2%2B4%2A0-7=highlight%28-7=y%29
As we see the graph:

Thank you,
Jojo