SOLUTION: Solve each system of equations. please help me with these.. thanks 5x + 4y - z = 1 2x - 2y + z = 1 -x - y + z - 2 x + y + z = 0 2x + 3y 1 2z = -1 x - y + z

Algebra ->  College  -> Linear Algebra -> SOLUTION: Solve each system of equations. please help me with these.. thanks 5x + 4y - z = 1 2x - 2y + z = 1 -x - y + z - 2 x + y + z = 0 2x + 3y 1 2z = -1 x - y + z       Log On


   



Question 177844: Solve each system of equations. please help me with these.. thanks


5x + 4y - z = 1
2x - 2y + z = 1
-x - y + z - 2





x + y + z = 0
2x + 3y 1 2z = -1
x - y + z = 2





x + 2y = 0
4x -z = 4
5y + z = -1

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
I think you meant – x – y + z = 2 for the 3rd equation in System # 1
5x + 4y - z = 1 ---------(i)
2x - 2y + z = 1 ---------(ii)
- x - y + z = 2 --------(iii)
Adding eq (i) and (ii) 7x + 2y = 2 -------------(iv)
Subtracting eq (iii) from eq (ii) 3x - y = -1 -------------(v)
Multiplying eq (iv) by 1 7x + 2y = 2 -------------(vi)
Multiplying eq (v) by 2 6x - 2y = -2 ------------(vii)
Adding eq (vi) and eq (vii) 13x = 0
x = 0
Substituting 0 for x in eq (v) 3(0) - y = -1
y = 1
Substituting 0 for x, & 1 for y in eq (i) 5x + 4y - z = 1
5(0) + 4(1) - z = 1
0 + 4 - z = 1
z = 3
Therefore, x = 0 ; y = 1 ; z = 3
You should be able to do the rest, although they seem to be missing information, or written incorrectly.