SOLUTION: I need to find an equation for a line whose points are (3,6) and (5,7). I have found the slope which is 1/2 and know the equation should be in the form of Y= mx + b. But I don't un
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-> SOLUTION: I need to find an equation for a line whose points are (3,6) and (5,7). I have found the slope which is 1/2 and know the equation should be in the form of Y= mx + b. But I don't un
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Question 14435: I need to find an equation for a line whose points are (3,6) and (5,7). I have found the slope which is 1/2 and know the equation should be in the form of Y= mx + b. But I don't understand how to calculate the value of b. Please help. Answer by atif.muhammad(135) (Show Source):
There is a formula for your problem
(y-y1) = m(x-x1)
where:
y = your y variable
y1 = your known y-value
m = gradient
x = your x variable
x1 = your known x-value
lets take one of the co-ordinates: (3,6)
you say the the gradient is 1/2.
Therefore, by subsituting in the value to my formula, I get:
(y-y1) = m(x-x1)
y = y
y1 = 6
m = 1/2
x = x
x1 = 3
(y-6) = 1/2 * (x-3)
y-6 = (x/2) - 3/2
y = (x/2) - 3/2 + 6
y = (x/2) + 9/2
y = 0.5x + 4.5
(