SOLUTION: Bryden got a job as a traffic helicopter pilot. She finds that with a tailwind, a 120km distance takes 45 minutes, but that the return trip (into the wind) takes 1 hour. What is
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Question 130096: Bryden got a job as a traffic helicopter pilot. She finds that with a tailwind, a 120km distance takes 45 minutes, but that the return trip (into the wind) takes 1 hour. What is the speed of the helicopter? What is the speed of the wind? Found 2 solutions by checkley71, stanbon:Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! (120+X)*.75=(120-X)*1
90+.75X=120-X
.75X+X=120-90
1.75X=30
X=30/1.75
X=17.143 IS THE WIND SPEED.
PROOF:
(120+17.143).75=120-17.143
137.143*.75=102.857
102.857=102.857
You can put this solution on YOUR website! Bryden got a job as a traffic helicopter pilot. She finds that with a tailwind, a 120km distance takes 45 minutes, but that the return trip (into the wind) takes 1 hour. What is the speed of the helicopter? What is the speed of the wind?
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Let speed of the helicopter be "h"; Let sped of the wind be "w".
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With the wind DATA:
Distance 120 km ; time = 0.75 hr. Rate = d/t = 120/0.75 = 160 kph
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Against the wind DATA:
Distance = 120 km ; time = 1 hr. Rate = d/t = 120 kph
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EQUATIONS:
h+w = 160
h-w = 120
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Add to solve for "h"
2h = 280
h = 140 kph (helicopter speed)
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Substitute to solve for "w"
140 + w = 160
w = 20 kph (wind speed)
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Cheers,
Stan H.
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