SOLUTION: The length of a rectangular enclosure is twice its width. The perimeter of the enclosure is 180 metres. Write down two simultaneous equations and Use Cramer’s rule to determine

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Question 1201941: The length of a rectangular enclosure is twice its width. The perimeter of the enclosure is 180 metres.
Write down two simultaneous equations and Use Cramer’s rule to determine the length and the width of the
enclosure.
Found 2 solutions by mananth, Alan3354:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangular enclosure is twice its width. The perimeter of the enclosure is 180 metres.
Write down two simultaneous equations and Use Cramer’s rule to determine the length and the width of the
enclosure.
The length of a rectangular enclosure is twice its width.
let width be x and length be y
As per the condition given y=2x or y-2x =0...............(1)
Perimeter of rectangle = 2L+2w
2x+2y = 180.........................(2) (divide by 2)
-2x+y =0
x+y =90
ly, type
.
By Cramer's rule x = dx/d = -90/-3 = 30 m
and y = dy/d = -180/-3 = 60 m






Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangular enclosure is twice its width. The perimeter of the enclosure is 180 metres.
Write down two simultaneous equations and Use Cramer’s rule to determine the length and the width of the enclosure.
-------------------------
P = 2W + 2L = 180
L = 2W
2W + 2*2W = 180
W = 30
etc