SOLUTION: Find value(s) of k such that y=kx-3 is tangent to the parabola y=2x^2+ 10

Algebra ->  College  -> Linear Algebra -> SOLUTION: Find value(s) of k such that y=kx-3 is tangent to the parabola y=2x^2+ 10      Log On


   



Question 1181587: Find value(s) of k such that y=kx-3 is tangent to the parabola y=2x^2+ 10
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Find value(s) of k such that y=kx-3 is tangent to the parabola y=2x^2+ 10
If you haven't had calculus, then we do it this way:

A line is tangent to a parabola if and only if the assumption of their
equations holding true leads to a single solution with multiplicity 2.

We substitute (kx-3) for y in 

y%22%22=%22%222x%5E2%2B10
kx-3%22%22=%22%222x%5E2%2B10

0%22%22=%22%222x%5E2%2Bkx%2B13

This will have a single solution with multiplicity 2 if its discriminant
equals 0.

b%5E2-4ac%22%22=%22%22k%5E2-4%282%29%2813%29k%5E2-104%22%22=%22%220

k%5E2%22%22=%22%22104
k%22%22=%22%22%22%22%2B-+sqrt%28104%29
k%22%22=%22%22%22%22%2B-+sqrt%284%2A26%29
k%22%22=%22%22%22%22%2B-+2sqrt%2826%29

Those are the two and the only such values of k.

Edwin