SOLUTION: Let vector space P2 have an inner product defined as
⟨p, q⟩ = ∫[-1 to 1] p(x)q(x) dx
Find d(1, x)
Algebra ->
College
-> Linear Algebra
-> SOLUTION: Let vector space P2 have an inner product defined as
⟨p, q⟩ = ∫[-1 to 1] p(x)q(x) dx
Find d(1, x)
Log On
Then d(1,x) is the inner product
(1-x,1-x) = integral from -1 to 1 of (1-x)^2 dx,
which is the same as the integral from -1 to 1 of (x-1)^2 dx.
Antiderivative is , and from it, you easily get the answer
= .
