SOLUTION: please explain:
Determine whether there is a maximum or minimum value for f(x) = -2x^2 + 3x + 4 and find that value
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Determine whether there is a maximum or minimum value for f(x) = -2x^2 + 3x + 4 and find that value
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Question 1139573: please explain:
Determine whether there is a maximum or minimum value for f(x) = -2x^2 + 3x + 4 and find that value Found 2 solutions by Alan3354, rothauserc:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Determine whether there is a maximum or minimum value for f(x) = -2x^2 + 3x + 4 and find that value
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The coefficient of the x^2 term is negative --> a maximum
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The max is the vertex of the parabola at x = -b/(2a) = -3/-4 = 3/4
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f(3/4) = -2*(3/4)^2 + 3*(3/4) + 4 = -9/8 + 9/4 + 4 = 41/8
You can put this solution on YOUR website! f(x) = -2x^2 + 3x + 4
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this is a parabola that curves downward, here is its graph
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the general form of a quadratic equation is
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f(x) = ax^2 +bx +c, where a, b, c are real numbers
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for the given equation, f(x) = -2x^2 + 3x + 4, a = -2, b = 3, c = 4
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the function maximum occurs at the parabola's vertex
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x coordinate = -b/2a = -3/(2 * (-2)) = 3/4
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f(3/4) = -2*(3/4)^2 +3*(3/4) +4 = 82/16 = 41/8 = 5.125
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the function maximum occurs at f(3/4) = 5.125
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