SOLUTION: Hi Tutors: I am suppose to find the slope and the y-intercept for :5x=2/3y-10 Do I start by dividing both sides by 1/5? Please point me in the right direction? Thank you in adv

Algebra ->  College  -> Linear Algebra -> SOLUTION: Hi Tutors: I am suppose to find the slope and the y-intercept for :5x=2/3y-10 Do I start by dividing both sides by 1/5? Please point me in the right direction? Thank you in adv      Log On


   

Question 11288: Hi Tutors:
I am suppose to find the slope and the y-intercept for :5x=2/3y-10 Do I start by dividing both sides by 1/5? Please point me in the right direction? Thank you in advance.
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
NO!! You need to solve for y, NOT solve for x.

+5x+=+%282%2F3%29%2A+y+-+10

I would begin by multiplying both sides by the denominator which is 3 to clear the denominator.
+3%2A+5x+=+3%2A%282%2F3%29%2A+y+-+3%2A10 Divide out the 3 on the right side:
+15x+=+2y+-+30

Add + 30 to each side to solve for y.
15x+%2B+30+=+2y

Divide both sides by 2:
%2815x%29%2F2+%2B+30%2F2+=+%282y%29%2F2
y+=+%2815%2F2%29%2Ax+%2B+15

Now that it is in slope-intercept form, the slope is the coefficient of x, which is 15%2F2 and the y-intercept is the constant, which is 15.

R^2 at SCC