SOLUTION: Find the vertex of the Quadratic Function f(x)=3(x+2)^2-8

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Question 1116148: Find the vertex of the Quadratic Function f(x)=3(x+2)^2-8
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Compare to y=a(x-h)^2+k. Vertex would be at (h,k).