SOLUTION: Find the length and width of a rectangle whose perimeter is 32 feet and whose area is 55 square feet

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Question 1103635: Find the length and width of a rectangle whose perimeter is 32 feet and whose area is 55 square feet
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
system%282x%2B2y=32%2Cxy=55%29

system%28x%2By=16%2Cxy=55%29

Any simple possibilities?
11 and 5 ?
Just the factorization for 55.
This combination works.
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Length, 11
Width, 5.
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Do you want Algebra instead?
y=16-x
-
x%2816-x%29=55
-x%5E2%2B16x=55
-x%5E2%2B16x-55=0
x%5E2-16x%2B55=0------and use either general solution or factoring.