SOLUTION: What is the equation of the line containing the points (-3,2) and (-6,3)?

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Question 10991: What is the equation of the line containing the points (-3,2) and (-6,3)?
Answer by rahman(247) About Me  (Show Source):
You can put this solution on YOUR website!
We can use this formula:
%28y-y1%29%2F%28y2-y1%29=%28x-x1%29%2F%28x2-x1%29
Suppose (-3,2) as (x1,y1) and (-6,3) as (x2,y2). So,
%28y-2%29%2F%283-2%29=%28x-%28-3%29%29%2F%28%28-6%29-%28-3%29%29
%28y-2%29%2F1=%28x%2B3%29%2F%28-6%2B3%29
%28y-2%29%2F1=%28x%2B3%29%2F-3
-3%28y-2%29=1%28x%2B3%29
-3y%2B6=x%2B3
-3y-x%2B6-3=0
-3y-x%2B3=0
Thus, the equation of the line containing the points (-3,2) and (-6,3) is -3y-x%2B3=0
Or,
-3y=x-3
y=%28-x%2F3%29%2B1
OK