SOLUTION: Write the equation of the line perpendicular to 3y -x = 2 and passing through (9, -10)

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Question 1092827: Write the equation of the line perpendicular to 3y -x = 2 and passing through (9, -10)
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
Write the equation of the line perpendicular to 3y+-x+=+2 and passing through (9, -10):
the equation of the line is: y=mx%2Bb where m is a slope and b is y-intercept
if given 3y+-x+=+2, first find a slope
3y+=+x%2B2
y+=+%281%2F3%29x%2B2%2F3-> m=1%2F3
the line perpendicular to given line must have a slope equal to negative reciprocal of m=1%2F3, and it is m%5Bp%5D=-1%2Fm=-1%2F%281%2F3%29=-3
so far your equation is

y=+-3x%2Bb
to find b use given point (9, -10)
-10=+-3%2A9%2Bb
-10=+-27%2Bb
-10%2B27=b
b=17
and of the line perpendicular to 3y+-x+=+2 is:

y=+-3x%2B17 or 3x%2By=17






Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Write the equation of the line perpendicular to 3y -x = 2 and passing through (9, -10)
To obtain the equation of a line that's perpendicular to another, we do the following: 
1) Put GIVEN equation in STANDARD form
2) Switch coefficients on variables, and change the constant to z
3) Negate y
4) Substitute GIVEN point to determine z
These steps should lead you to the required equation: highlight_green%28matrix%281%2C3%2C+3x+%2B+y%2C+%22=%22%2C+17%29%29