SOLUTION: a person spent 3/5 of his money in first store, and then $2 on parking. he then spent 1/3 of what is left in 2nd store. at the end he had $12 left. how much money he started he had
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Question 1084702: a person spent 3/5 of his money in first store, and then $2 on parking. he then spent 1/3 of what is left in 2nd store. at the end he had $12 left. how much money he started he had started with?
Thanks, appreciate your help Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! Let M = the initial amount
Amount spent at first store + parking = (3/5)M + 2
The amount remaining is M - [(3/5)M + 2] = (2/5)M - 2
1/3 of this was spent at the 2nd store, and the amount remaining was $12:
(2/5)M - 2 - (1/3)*( (2/5)M - 2 ) = 12
Solve for M:
(4/15)M - (4/3) = 12
M = (40/3)*(15/4) = $50
Check:
1st store + parking (3/5)*50 + 2 = $32
50 - 32 = 18 left
18 - (1/3)18 = 12
