Question 1075449: Given vectors:
OP = <4,1,-6>
OQ = <2,-7,5>
OR = <3,-2,4>
Find the scalar n in OP+nOQ that is perpendicular to OR.
Thx!
Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website! Given vectors:
OP = <4,1,-6>
OQ = <2,-7,5>
OR = <3,-2,4>
Find the scalar n in OP+nOQ that is perpendicular to OR.
OP+nOQ = <4,1,-6> + n<2,-7,5> = <4,1,-6> + <2n,-7n,5n> =
<4+2n,1-7n,-6+5n>
Two vectors are perpendicular if and only if their scalar
(dot)-product is 0, so we set the dot product (OP+nOQ)•OR = 0,
or
<4+2n,1-7n,-6+5n>•<3,-2,4> = 3(4+2n)-2(1-7n)+4(-6+5n) =
12+6n-2+14n-24+20n = 0
-14+40n = 0
40n = 14
n = 14/40
n = 7/20
Edwin
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