SOLUTION: i need help solving these quadratic equations using the quadratic formula. 2x^2 - 5x = 3 3x^2 - 2x + 1 = 0

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Question 107039: i need help solving these quadratic equations using the quadratic formula.
2x^2 - 5x = 3
3x^2 - 2x + 1 = 0
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You need to get them into the right form in
order to use the quadratic equation.. The right
form is ax%5E2+%2B+bx+%2B+c+=+0
2x%5E2+-+5x+=+3
2x%5E2+-+5x+-+3+=+0
a = 2
b = -5
c = -3
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2-4%2A2%2A%28-3%29+%29%29%2F%282%2A2%29+
x+=+%285+%2B-+sqrt%2825+%2B+24+%29%29%2F4+
x+=+%285+%2B-+sqrt%2849+%29%29%2F4+
x+=+%285+%2B+7%29%2F4
x+=+3 answer
and
x+=+%285+-+7%29%2F4
-%281%2F2%29 answer
You can substitute both answers back into the equation to check them
-------------------------------
3x%5E2+-+2x+%2B+1+=+0
a = 3
b = -2
c = 1
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%2A3%2A1+%29%29%2F%282%2A3%29+
x+=+%282+%2B-+sqrt%28+4+-+12+%29%29%2F6+
x+=+%282+%2B-+sqrt%28-8%29%29%2F6
x+=+%282+%2B+2%2Asqrt%282%29i%29%2F6
x+=+1%2F3+%2B+%28sqrt%282%29%2F3%29i answer
x+=+%282+-+2%2Asqrt%282%29i%29%2F6
x+=+1%2F3+-+%28sqrt%282%29%2F3%29i answer
I checked the 2nd answer OK, It's tricky keeping
track of signs. Remember i%2Ai+=+-1