Question 1049820: hi I would like to know how to find the quadratic polynomial whose graph goes through the points (−1,2),(−1,2), (0,2),(0,2), and (2,14)
thank you
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find the quadratic polynomial whose graph goes through the points (−1,2),(0,2), and (2,14)
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Form::
ax^2 + bx + c = y
Using (-1,2) you get:: a - b + c = 2
Using (0,2) you get:: 0 - 0 + c = 2
Using (2,14) you get:: 4a + 2b + c = 14
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Notice that c = 2, you can write two equations in a and b::
a - b = 0
4a+2b = 12
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a - b = 0
2a + b = 6
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Add and solve for "a"::
3a = 6
a = 2
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Solve for "b":
a - b = 0
2 - b = 0
b = 2
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Equation:
y = 2x^2 + 2x + 2
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Cheers,
Stan H.
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