SOLUTION: A rental car cost $22 per day plus $0.40 per mile.If someone has $350 to spend and needs to drive the car 60 miles each day, for how many days can that person rent the​ car?

Algebra ->  College  -> Linear Algebra -> SOLUTION: A rental car cost $22 per day plus $0.40 per mile.If someone has $350 to spend and needs to drive the car 60 miles each day, for how many days can that person rent the​ car?       Log On


   

Question 1046695: A rental car cost $22 per day plus $0.40 per mile.If someone has $350 to spend and needs to drive the car 60 miles each day, for how many days can that person rent the​ car? Assume that the car cannot be rented for part of a day.
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Look for how to form equations to account for cost and for distance.

How many days? x days.
How many miles? 60x%28miles%29
Cost contribution due to distance? %280.4%29%2A60x=24x%28dollars%29
Cost contribution due to days? 22%2Ax%28dollars%29

Now the thought is accounting form distance is not really an equation to look for.

Finishing accounting for cost,
highlight_green%2822x%2B24x=350%29

46x=350
23x=175
x=175%2F23
x=7.609
This can only be the WHOLE numbered part for count of days.
highlight%28x=7%29