SOLUTION: find the basic for the subspace of IR^4 spanned by s: s={(2,9,-2,53),(-3,2,3,-2),(8,-3,-8,17),(0,-3,0,15)}.

Algebra ->  College  -> Linear Algebra -> SOLUTION: find the basic for the subspace of IR^4 spanned by s: s={(2,9,-2,53),(-3,2,3,-2),(8,-3,-8,17),(0,-3,0,15)}.      Log On


   



Question 1044796: find the basic for the subspace of IR^4 spanned by s:
s={(2,9,-2,53),(-3,2,3,-2),(8,-3,-8,17),(0,-3,0,15)}.

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Is the fourth vector really (0,-3,0,15), or (0,-3,0,-15)?