SOLUTION: Write the equation of a line that passes through (0,6) and is perpendicular to x-3y=5

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Question 1021683: Write the equation of a line that passes through (0,6) and is perpendicular to x-3y=5
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
Original equation:
x-3y=5
x-5=3y
(1/3)x-(5/3)=y
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y=(1/3)x-(5/3) (RED line on graph)
.
The slope of the original line is 1/3,
so the slope of the perpendicular line would be -3.
.
Use x=0 and y=6 to find b.
y=mx+b
y=-3x+b
6=-3(0)+b
6=b
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ANSWER: The equation is y=-3x+6 (GREEN line on graph)
.
GRAPH:
+graph%28+800%2C+800%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F3%29x%2B%285%2F3%29%2C+-3x%2B6%29+