SOLUTION: Find the slope-intercept form of the equation that passes through the given point and is perpendicular to the given line.
(6,-1) and 3y+x=3
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(6,-1) and 3y+x=3
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Question 1001267: Find the slope-intercept form of the equation that passes through the given point and is perpendicular to the given line.
(6,-1) and 3y+x=3 Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! From 3y+x=3, let's put it into slope-intercept form to find the slope...
3y = -x + 3
y (-1/3)x + 1
So if we need a perpendicular line it is the negative reciprocal of (-1/3).
That would be 3.
Now plug that and the point (6,-1) into y = mx + b to find b:
-1 = 3(6) + b
-1 = 18 + b
b = -19
and
y = 3x - 19
