SOLUTION: Find the value of K so that the equation 3x2−6x+k=0
a)two real solutions.
b)two complex solutions.
c)one real(or two same) solution(s)
this is question in my homework
Algebra ->
Absolute-value
-> SOLUTION: Find the value of K so that the equation 3x2−6x+k=0
a)two real solutions.
b)two complex solutions.
c)one real(or two same) solution(s)
this is question in my homework
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Question 847229: Find the value of K so that the equation 3x2−6x+k=0
a)two real solutions.
b)two complex solutions.
c)one real(or two same) solution(s)
this is question in my homework. Answer by swincher4391(1107) (Show Source):
You can put this solution on YOUR website! a=3 b=-6 c = k
Find b^2 -4ac:
36 - 12k
This is our discriminant.
Now when D > 0 we have two real solutions
36 -12k > 0
-12k > -36
k < 3
When D < 0 we have two complex solutions
36- 12k < 0
-12k < -36
k > 3
When D = 0 we have one real solution
36-12k= 0
36 = 12k
k = 3
