SOLUTION: A bicyclist rode into the country for 5 h. In returning, her speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?
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-> SOLUTION: A bicyclist rode into the country for 5 h. In returning, her speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?
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Question 67530: A bicyclist rode into the country for 5 h. In returning, her speed was 5 mi/h faster and the trip took 4 h. What was her speed each way? Answer by ptaylor(2198) (Show Source):
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Let x=her speed going in
Then x+5= her speed returning
distance (d)= rate (r) times time (t) or d=rt
distance going=distance returning
distance going=5x
distance returning=4(x+5)
So 5x=4(x+5)
5x=4x+20 subtract 4x from both sides
5x-4x=20
x=20mph----------------------------speed going in
x+5=20+5=25mph----------------------speed returning
Ck
4 hours at 25 mph=5 hours at 20 mph
100=100
and
25=20+5
25=25
