SOLUTION: I need to rewrite without absolute value sign; |x-2|-2|3x-12|,|x-10|-2|2x+4|+3|4x-4|, (if -5<x<-2) |x-1|-3|5x-25|+|x|. Can you explain how to do rewrite these?

Algebra ->  Absolute-value -> SOLUTION: I need to rewrite without absolute value sign; |x-2|-2|3x-12|,|x-10|-2|2x+4|+3|4x-4|, (if -5<x<-2) |x-1|-3|5x-25|+|x|. Can you explain how to do rewrite these?      Log On


   

Question 1118540: I need to rewrite without absolute value sign;
|x-2|-2|3x-12|,|x-10|-2|2x+4|+3|4x-4|, (if -5
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I need to rewrite without absolute value sign;
If -5< x<-2 |x-2|-2|3x-12|
x-2 is negative
3x-12 is negative
You get: -(x-2)-2[-(3x-12)] = -x+2-[-3x+12] = -x+2+3x-12 = 2x-10
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|x-10|-2|2x+4|+3|4x-4|
If -5 < x < -2
x-10 is negative
2x+4 is negative
4x-4 is negative
You get -(x-10)-2(-2x-4)+3(-4x-4) = -x+10 +4x+8 -12x-12 = -9x+6
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(if -5 x-1 is negative
5x-25 is negative
x is negative
You get -(x-1) -2(-5x+25)-x = -x+1+10x-50-x = 8x-49
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Cheers,
Stan H.
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