SOLUTION: we have 100 coins, a mixture of nickels and dimes, with a total value of $8.20. how many of each type of coin do we have? how would I go about solving this?

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Question 945570: we have 100 coins, a mixture of nickels and dimes, with a total value of $8.20. how many of each type of coin do we have?
how would I go about solving this?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
"we have 100 coins, a mixture of nickels and dimes"

so we know that n%2Bd+=+100 where

n = number of nickels
d = number of dimes

you can solve for either variable. I'm going to solve for d: d+=+100-n

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The total value of the coins is $8.20, so we also know

0.05n+%2B+0.10d+=+8.20

0.05n+%2B+0.10%28100-n%29+=+8.20 Plug in d+=+100-n

0.05n+%2B+10+-+0.10n+=+8.20

-0.05n+%2B+10+=+8.20

Keep going to solve for n. I'll let you do that. Once you find the value of n, you plug it into d+=+100-n to get the value of d.