SOLUTION: I am stuck on this problem and need help. You have 53 coins consisting of dimes and pennies. The number of pennies is 7 less than twice the number of dimes. 1.) How many pe

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: I am stuck on this problem and need help. You have 53 coins consisting of dimes and pennies. The number of pennies is 7 less than twice the number of dimes. 1.) How many pe      Log On

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Question 917170: I am stuck on this problem and need help.
You have 53 coins consisting of dimes and pennies. The number of pennies is 7 less than twice the number of dimes.
1.) How many pennies do you have?
2.) How many dimes do you have?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x the number of dimes
53 coins
# ofdimes + # of pennies = 53
x + (2x-7) = 53
3x = 60
x = 20, the number of dimes and 33 pennies 2%2A20-7
and...checking
20 + 33 = 53 coins